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public MyClass(int i, int j) { alpha = i; beta = j; } // Return true if ob contains the same values as the invoking object public bool SameAs(MyClass ob) { if((obalpha == alpha) & (obbeta == beta)) return true; else return false; } // Make a copy of ob public void Copy(MyClass ob) { alpha = obalpha; beta = obbeta; } public void Show() { ConsoleWriteLine("alpha: {0}, beta: {1}", alpha, beta); } } class PassOb { static void Main() { MyClass ob1 = new MyClass(4, 5); MyClass ob2 = new MyClass(6, 7); ConsoleWrite("ob1: "); ob1Show(); ConsoleWrite("ob2: "); ob2Show(); if(ob1SameAs(ob2)) ConsoleWriteLine("ob1 and ob2 have the same values"); else ConsoleWriteLine("ob1 and ob2 have different values"); ConsoleWriteLine(); // Now, make ob1 a copy of ob2 ob1Copy(ob2); ConsoleWrite("ob1 after copy: "); ob1Show(); if(ob1SameAs(ob2)) ConsoleWriteLine("ob1 and ob2 have the same values"); else ConsoleWriteLine("ob1 and ob2 have different values"); } }

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2 0

Part I:

Princess Diana vs Diana, the princess Ms Mary Watkins President Washington vs Washington, the rst president of the United States of America

This program generates the following output:

ob1: alpha: 4, beta: 5 ob2: alpha: 6, beta: 7 ob1 and ob2 have different values ob1 after copy: alpha: 6, beta: 7 ob1 and ob2 have the same values

2 4

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The SameAs( ) and Copy( ) methods each take a reference of type MyClass as an argument The SameAs( ) method compares the values of alpha and beta in the invoking object with the values of alpha and beta in the object passed via ob The method returns true only if the two objects contain the same values for these instance variables The Copy( ) method assigns the values of alpha and beta in the object referred to by ob to alpha and beta in the invoking object As this example shows, syntactically, reference types are passed to methods in the same way as are value types

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As the preceding example demonstrated, passing an object reference to a method is a straightforward task However, there are some nuances that the example did not show In certain cases, the effects of passing a reference type will be different than those experienced when passing a value type To see why, let s review the two ways in which an argument can be passed to a subroutine The first way is call-by-value This method copies the value of an argument into the formal parameter of the subroutine Therefore, changes made to the parameter of the subroutine have no effect on the argument used in the call The second way an argument can be passed is call-by-reference In this method, a reference to an argument (not the value of the argument) is passed to the parameter Inside the subroutine, this reference is used to access the actual argument specified in the call This means that changes made to the parameter will affect the argument used to call the subroutine By default, C# uses call-by-value, which means that a copy of the argument is made and given to the receiving parameter Thus, when you pass a value type, such as int or double, what occurs to the parameter that receives the argument has no effect outside the method For example, consider the following program:

// Value types are passed by value using System; class Test { /* This method causes no change to the arguments used in the call */ public void NoChange(int i, int j) { i = i + j; j = -j; } } class CallByValue { static void Main() { Test ob = new Test();

12 Do each of the problems in Exercise 11 with method of rectangles replaced by trapezoid rule

8:

int a = 15, b = 20; ConsoleWriteLine("a and b before call: " + a + " " + b); obNoChange(a, b); ConsoleWriteLine("a and b after call: " + a + " " + b); } }

The output from this program is shown here:

2 Capitalizing job titles is generally not recommended by style guides, although many companies do so If you do, be consistent If a job title precedes the job holder s name, then capitalize it

a and b before call: 15 20 a and b after call: 15 20

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