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1 The number 396545454 written as a rational fraction is (a) 3894/999 (b) 3152/1000 (c) 39258/9900 (d) 41445/9999 (e) 5312/2122 2 The intersection of the sets [2, 4] and (3, 6) is (a) (3, 4] (b) [2, 6) (c) (3, 5) (d) (2, 6] (e) [3, 4] 3 The intersection of the sets {(x, y) : x 2 + y2 < 1} and {(x, y) : y > 0} is (a) a half-disc with boundary (b) a quarter-disc (c) a disc without boundary (d) a disc with boundary (e) a half-disc without boundary 4 The line through the points (2, 4) and (1, 6) has slope (a) 10 (b) 10 (c) 5 (d) 3 (e) 2

As you can see, the operations that occur inside NoChange( ) have no effect on the values of a and b used in the call Again, this is because copies of the value of a and b have been given to parameters i and j, but a and b are otherwise completely independent of i and j Thus, assigning i a new value will not affect a When you pass a reference to a method, the situation is a bit more complicated In this case, the reference, itself, is still passed by value Thus, a copy of the reference is made and changes to the parameter will not affect the argument (For example, making the parameter refer to a new object will not change the object to which the argument refers) However and this is a big however changes made to the object being referred to by the parameter will affect the object referred to by the argument Let s see why Recall that when you create a variable of a class type, you are only creating a reference to an object Thus, when you pass this reference to a method, the parameter that receives it will refer to the same object as that referred to by the argument Therefore, the argument and the parameter will both refer to the same object This means that objects are passed to methods by what is effectively call-by-reference Thus, changes to the object inside the method do affect the object used as an argument For example, consider the following program:

// Objects are passed by reference using System; class Test { public int a, b; public Test(int i, int j) { a = i; b = j; } /* Pass an object Now, oba and obb in object used in the call will be changed */ public void Change(Test ob) { oba = oba + obb; obb = -obb; } }

Part I:

5 The equation of the line through (1, 2) that is perpendicular to y = 3x + 6 is (a) y 1 = [1/3](x 2) (b) y 2 = 3(x 1) (c) y = [1/3](x + 1) (d) y 2 = [ 1/3](x 1) (e) y 2 = [1/3](x 1) 6 The equation of the line through ( 2, 5) that is parallel to y = 4x + 2 is (a) y 5 = 4(x + 2) (b) y 2 = 4(x + 5) (c) y + 5 = 4(x 2) (d) y 5 = 4(x 2) (e) y + 2 = 4(x 5) 7 The line passing through the points (2, 1) and (5, 3) has equation (a) y + 2 = [3/2](x + 1) (b) y 2 = [2/3](x 1) (c) y 1 = [ 2/3](x 2) (d) y 1 = [2/3](x 2) (e) y + 1 = [2/3](x + 2) 8 The equation y + y2 3x + 2 = 0 describes (a) a circle (b) a parabola (c) a line (d) a cardioid (e) an ellipse 9 The curve y = x 3 intersects the line y = x (a) in a segment (b) in a circle (c) in an arc (d) in two points (e) in one point 10 The sine of an angle is always (a) between 1 and 2 inclusive (b) between 1 and 0 exclusive (c) between 1 and 1 inclusive

class CallByRef { static void Main() { Test ob = new Test(15, 20); ConsoleWriteLine("oba and obb before call: " + oba + " " + obb); obChange(ob); ConsoleWriteLine("oba and obb after call: " + oba + " " + obb); } }

This program generates the following output:

oba and obb before call: 15 20 oba and obb after call: 35 -20

As you can see, in this case, the actions inside Change( ) have affected the object used as an argument To review: When a reference is passed to a method, the reference itself is passed by use of call-by-value Thus, a copy of that reference is made However, the copy of that reference will still refer to the same object as its corresponding argument This means that objects are implicitly passed using call-by-reference