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2 is prime 3 is prime 4 is not prime 5 is prime 6 is not prime 7 is prime 8 is not prime 9 is not prime Least common factor for 7 and 8 is 1 Least common factor for 100 and 8 is 2 Least common factor for 100 and 75 is 5

2 f (x j ) 1 + [ f (x j )]2

When using multiple parameters, each parameter specifies its own type, which can differ from the others For example, this is perfectly valid:

int MyMeth(int a, double b, float c) { //

6:

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f (x) 1 + [ f (x)]2

You can use a parameterized method to add a new feature to the Building class: the ability to compute the maximum number of occupants for a building assuming that each occupant must have a certain minimal space This new method is called MaxOccupant( ) It is shown here:

Who was there I will respond to whoever provides the answers You saw whom I will consult with whomever I want

// Return the maximum number of occupants if each // is to have at least the specified minimum area public int MaxOccupant(int minArea) { return Area / minArea; }

When MaxOccupant( ) is called, the parameter minArea receives the minimum space needed for each occupant The method divides the total area of the building by this value and returns the result The entire Building class that includes MaxOccupant( ) is shown here:

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/* Add a parameterized method that computes the maximum number of people that can occupy a building assuming each needs a specified minimum space */ using System; class Building { public int Floors; // number of floors public int Area; // total square footage of building public int Occupants; // number of occupants // Return the area per person public int AreaPerPerson() { return Area / Occupants; } // Return the maximum number of occupants if each // is to have at least the specified minimum area public int MaxOccupant(int minArea) { return Area / minArea; } } // Use MaxOccupant() class BuildingDemo { static void Main() { Building house = new Building(); Building office = new Building(); // Assign values to fields in house houseOccupants = 4; houseArea = 2500; houseFloors = 2;

As the mesh of the partition gets finer, the sum ( ) more closely approximates what we think of as the area of the surface, but it also converges to the integral We conclude that the integral

Part I:

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// Assign values to fields in office officeOccupants = 25; officeArea = 4200; officeFloors = 3; ConsoleWriteLine("Maximum occupants for house if each has " + 300 + " square feet: " + houseMaxOccupant(300)); ConsoleWriteLine("Maximum occupants for office if each has " + 300 + " square feet: " + officeMaxOccupant(300)); } }

The output from the program is shown here:

f (x) 1 + [ f (x)]2

Maximum occupants for house if each has 300 square feet: 8 Maximum occupants for office if each has 300 square feet: 14

When creating methods, you should avoid causing a situation in which a portion of code cannot, under any circumstances, be executed This is called unreachable code, and it is considered incorrect in C# The compiler will issue a warning message if you create a method that contains unreachable code For example:

public void MyMeth() { char a, b; // if(a==b) { ConsoleWriteLine("equal"); return; } else { ConsoleWriteLine("not equal"); return; } ConsoleWriteLine("this is unreachable"); }

The easiest way to con rm that you re using who and whom correctly is to follow this three-step process: 1 Identify all the verbs in the sentence 2 Identify all the subjects that go with these verbs 3 If the word you re looking to replace is the subject of the sentence or a dependent clause, use who or whoever If the word you re looking to replace is not the subject, use whom or whomever

Let f ( x) = 2x 3 For 1 x 2 we rotate the graph of f about the x axis Calculate the resulting surface area

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